Midpoint | Coordinate Geometry | CBSE | Class 10 | Math
Shiksha Abhiyan
Add to My Podcasts
Episodes
About
Reviews
Promote
Q3. In Δ ABC ∠B = 90° and D is the mid-point of BC. Prove that AC² = AD² + 3CD².
4 minutes
Posted Sep 29, 2020 at 12:25 pm.
0:00
4:11
Add to My Queue
Download
MP3
Share
episode
Share at current time
Show notes
This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||
Previous
Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)
← See all 3 episodes of Midpoint | Coordinate Geometry | CBSE | Class 10 | Math
