Midpoint | Coordinate Geometry | CBSE | Class 10 | Math
Shiksha Abhiyan
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Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)
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Posted Sep 28, 2020 at 4:40 pm.
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This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||
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Q1. In ∆ ABC, angle B = 90° and D is the midpoint of BC. Prove that AC² = AD² +3CD²
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Q3. In Δ ABC ∠B = 90° and D is the mid-point of BC. Prove that AC² = AD² + 3CD².
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